MHT CET · Chemistry · Solid State
Calculate the number of atoms in 0.3 gram metal if it forms bec structure \(\left[\rho \times \mathrm{a}^3=3 \times 10^{-22} \mathrm{~g}\right]\)
- A \(1.0 \times 10^{21}\)
- B \(2.0 \times 10^{21}\)
- C \(3.0 \times 10^{21}\)
- D \(4.0 \times 10^{21}\)
Answer & Solution
Correct Answer
(B) \(2.0 \times 10^{21}\)
Step-by-step Solution
Detailed explanation
For bec unit cell, \(\mathrm{n}=2\).
No. of particles in \(x \mathrm{~g}=\frac{x \mathrm{n}}{\rho \mathrm{a}^3}\)
\(\therefore \quad\) Number of atoms in 0.3 g of metal \(=\frac{0.3 \times 2}{3 \times 10^{-22}}=2.0 \times 10^{21}\) atoms
No. of particles in \(x \mathrm{~g}=\frac{x \mathrm{n}}{\rho \mathrm{a}^3}\)
\(\therefore \quad\) Number of atoms in 0.3 g of metal \(=\frac{0.3 \times 2}{3 \times 10^{-22}}=2.0 \times 10^{21}\) atoms
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