MHT CET · Chemistry · Some Basic Concepts of Chemistry
Calculate the molar mass of solute when 4 g of it dissolved in \(1 \mathrm{dm}^3\). solvent has osmotic pressure 2 atm at \(300 \mathrm{~K} .\left[\mathrm{R}=0 . \hat{0} 82 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right]\)
- A \(49.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(44.5 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(54.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(56.4 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(A) \(49.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{M}_2 & =\frac{\mathrm{W}_2 \mathrm{RT}}{\pi \mathrm{V}} \\ & =\frac{4 \mathrm{~g} \times 0.082 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \times 300 \mathrm{~K}}{2 \mathrm{~atm} \times 1 \mathrm{dm}^3} \\ & =49.2 \mathrm{~g} \mathrm{~mol}^{-1}\end{aligned}\)
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