MHT CET · Chemistry · Solutions
Calculate the molar mass of solute when 1.5 gram nonvolatile solute dissolved in \(100 \mathrm{~mL}\) solvent having density \(0.8 \mathrm{~g} \mathrm{~mL}^{-1}\) lowers its freezing point by \(0.75 \mathrm{~K}\).
(Freezing point depression constant for solvent is \(5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\) )
- A \(125 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(110 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(100 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(75 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(A) \(125 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta T_f=k_f \cdot \frac{W_B}{M_B} \times \frac{1000}{W_A} \\ & 0.75=5 \times \frac{1.5}{M_B} \times \frac{1000}{80} \\ & M_B=125 \mathrm{~g} / \mathrm{mol}\end{aligned}\)
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