MHT CET · Chemistry · Solutions
Calculate the molar mass of solute in a solution prepared by dissolving 1 gram in \(0.3 \mathrm{dm}^3\) solvent having osmotic pressure 0.2 atm at 300 K.
\(\left[\mathrm{R}=0.082 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K} \mathrm{~mol}^{-1}\right]\)
- A \(442 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(372 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(390 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(410 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(D) \(410 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{M}_2 & =\frac{\mathrm{W}_2 \mathrm{RT}}{\pi \mathrm{V}} \\ & =\frac{1 \mathrm{~g} \times 0.0821 \mathrm{dm}^3 \mathrm{atmK}^{-1} \mathrm{~mol}^{-1} \times 300 \mathrm{~K}}{0.2 \mathrm{~atm} \times 0.3 \mathrm{dm}^3} \\ & =410 \mathrm{~g} \mathrm{~mol}^{-1}\end{aligned}\)
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