MHT CET · Chemistry · Solid State
Calculate the molar mass of metal having density \(22.24 \mathrm{~g} \mathrm{~cm}^{-3}\), crystallizes to form unit cell containing 4 particles.
\(\left(\mathrm{a}^3=5.6 \times 10^{-23} \mathrm{~cm}^3\right)\)
- A \(280.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(140 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(210.6 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(187.4 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(D) \(187.4 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{d}=\frac{\mathrm{Z} \times \mathrm{M}}{\mathrm{V} \times \mathrm{N}_{\mathrm{A}}}=\frac{4 \times \mathrm{M}}{5.6 \times 10^{-23} \times 6.02 \times 10^{23}}\)
or \(22.24=\frac{4 \times M}{5.6 \times 6.02}\)
\(\mathrm{M}=187.43 \mathrm{~g} / \mathrm{mol}\)
or \(22.24=\frac{4 \times M}{5.6 \times 6.02}\)
\(\mathrm{M}=187.43 \mathrm{~g} / \mathrm{mol}\)
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