MHT CET · Chemistry · Solid State
Calculate the molar mass of an element with density \(2.7 \mathrm{~g} \mathrm{~cm}^{-3}\) that forms fcc structure.
\(\left[\mathrm{a}^3 \cdot \mathrm{N}_{\mathrm{A}}=40 \mathrm{~cm}^3 \mathrm{~mol}^{-1}\right]\)
- A \(112 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(54 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(27 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(78 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(C) \(27 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
For fcc unit cell, \(n=4\).
\(\begin{aligned}
& \text { Density }(\rho)=\frac{M \text { n }}{a^3 N_A} \\
& 2.7=\frac{M \times 4}{40} \\
& M=\frac{2.7 \times 40}{4}=27 \mathrm{~g} \mathrm{~mol}^{-1}
\end{aligned}\)
\(\begin{aligned}
& \text { Density }(\rho)=\frac{M \text { n }}{a^3 N_A} \\
& 2.7=\frac{M \times 4}{40} \\
& M=\frac{2.7 \times 40}{4}=27 \mathrm{~g} \mathrm{~mol}^{-1}
\end{aligned}\)
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