MHT CET · Chemistry · Solutions
Calculate the molality of nonvolatile solution if solution freezes at \(-0.95^{\circ} \mathrm{C}\left[\mathrm{K}_{\mathrm{f}}\right.\) for water \(=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\), freezing point of water \(\left.=0^{\circ} \mathrm{C}\right]\)
- A \(0.032 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- B \(0.041 \mathrm{~mol} \mathrm{~kg} \mathrm{~kg}^{-1}\)
- C \(0.051 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- D \(0.065 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Answer & Solution
Correct Answer
(C) \(0.051 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Step-by-step Solution
Detailed explanation
\( \Delta T_f = 0^{\circ} \mathrm{C} - (-0.95^{\circ} \mathrm{C}) = 0.95^{\circ} \mathrm{C} = 0.95 \mathrm{~K} \) \( m = \frac{\Delta T_f}{K_f} = \frac{0.95 \mathrm{~K}}{1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}} = 0.51075 \mathrm{~mol} \mathrm{~kg}^{-1} \approx 0.051 \mathrm{~mol} \mathrm{~kg}^{-1} \)
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