MHT CET · Chemistry · Solutions
Calculate the molal elevation constant of solvent if boiling point of 0.12 m solution is 319.8 K (Boling point of solvent \(=319.5 \mathrm{~K}\) )
- A \(2 \cdot 0 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
- B \(3.0 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
- C \(2.5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
- D \(3 \cdot 5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(C) \(2.5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
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