MHT CET · Chemistry · Ionic Equilibrium
Calculate the ionisation constant of \(0.08 \mathrm{~mol~} \mathrm{dm}^{-3}\) of a monobasic acid having \(\mathrm{pH}=2\)
- A \(3.531 \times 10^{-7}\)
- B \(2.081 \times 10^{-6}\)
- C \(3.456 \times 10^{-8}\)
- D \(1.25 \times 10^{-3}\)
Answer & Solution
Correct Answer
(D) \(1.25 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
\([H^+] = 10^{-pH} = 10^{-2} \mathrm{~mol~} \mathrm{dm}^{-3}\) \(K_a = \frac{[H^+]^2}{C} = \frac{(10^{-2})^2}{0.08}\)
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