MHT CET · Chemistry · Ionic Equilibrium
Calculate the ionic concentration of sparingly soluble salt BA in mol dm \({ }^{-3}\) at 300 K when equilibrium is attained if solubility product of salt is \(2.7 \times 10^{-10}\) at same temperature.
- A \(1.123 \times 10^{-5}\)
- B \(2.051 \times 10^{-5}\)
- C \(2.263 \times 10^{-5}\)
- D \(1.643 \times 10^{-5}\)
Answer & Solution
Correct Answer
(D) \(1.643 \times 10^{-5}\)
Step-by-step Solution
Detailed explanation
\(K_{sp} = s^2\) \(2.7 \times 10^{-10} = s^2\)
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