MHT CET · Chemistry · Ionic Equilibrium
Calculate the equilibrium concentration of \(\mathrm{Pb}^{++}\)ions in a solution of PbS containing \(1 \times 10^{-11} \mathrm{~mol~} \mathrm{dm}{ }^{-3}\) of sulphide ions.
(Given \(\mathrm{K}_{\mathrm{sp}}\) for \(\mathrm{PbS}=8.0 \times 10^{-28}\) )
- A \(4 \times 10^{-14}\)
- B \(4 \times 10^{-17}\)
- C \(8 \times 10^{-17}\)
- D \(8 \times 10^{-11}\)
Answer & Solution
Correct Answer
(C) \(8 \times 10^{-17}\)
Step-by-step Solution
Detailed explanation
\([\mathrm{Pb}^{++}] = \frac{\mathrm{K}_{\mathrm{sp}}}{[\mathrm{S}^{--}]}\) \([\mathrm{Pb}^{++}] = \frac{8.0 \times 10^{-28}}{1 \times 10^{-11}}\)
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