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MHT CET · Chemistry · Ionic Equilibrium

Calculate the equilibrium concentration of \(\mathrm{Pb}^{++}\)ions in a solution of PbS containing \(1 \times 10^{-11} \mathrm{~mol~} \mathrm{dm}{ }^{-3}\) of sulphide ions.
(Given \(\mathrm{K}_{\mathrm{sp}}\) for \(\mathrm{PbS}=8.0 \times 10^{-28}\) )

  1. A \(4 \times 10^{-14}\)
  2. B \(4 \times 10^{-17}\)
  3. C \(8 \times 10^{-17}\)
  4. D \(8 \times 10^{-11}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(8 \times 10^{-17}\)

Step-by-step Solution

Detailed explanation

\([\mathrm{Pb}^{++}] = \frac{\mathrm{K}_{\mathrm{sp}}}{[\mathrm{S}^{--}]}\) \([\mathrm{Pb}^{++}] = \frac{8.0 \times 10^{-28}}{1 \times 10^{-11}}\)