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MHT CET · Chemistry · Thermodynamics (C)

Calculate the entropy change for melting 1 g ice at \(0^{\circ} \mathrm{C}\) in \(\mathrm{Jg}^{-1} \mathrm{~K}^{-1}\) if heat of fusion of ice at \(0^{\circ} \mathrm{C}\) is \(80 \mathrm{~J} \mathrm{~K}^{-1}\).

  1. A 0.039
  2. B 0.293
  3. C 8
  4. D 27.3
Verified Solution

Answer & Solution

Correct Answer

(B) 0.293

Step-by-step Solution

Detailed explanation

For the reaction,
\(\mathrm{H}_2 \mathrm{O}_{(\mathrm{s})} \rightleftharpoons \mathrm{H}_2 \mathrm{O}_{(l)}\)
The change in Gibbs energy at constant temperature and constant pressure is given by,
\(\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{~S}\)
At equilibrium, \(\Delta \mathrm{G}=0\)
\(\therefore \Delta \mathrm{S}=\frac{\Delta \mathrm{H}_{\text {fusion }}}{\mathrm{T}}=\frac{80}{273}=0.293\left(\because 0^{\circ} \mathrm{C}=273 \mathrm{~K}\right)\)
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