MHT CET · Chemistry · Solid State
Calculate the edge length of unit cell of metal which crystallises to bcc structure.
(Radius of metal atom \(=173 \mathrm{pm}\) )
- A \(5.01 \times 10^{-8} \mathrm{~cm}\)
- B \(4.00 \times 10^{-8} \mathrm{~cm}\)
- C \(4.5 \times 10^{-8} \mathrm{~cm}\)
- D \(5.5 \times 10^{-8} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(4.00 \times 10^{-8} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
For bcc unit cell, \(r=\frac{\sqrt{3}}{4} \mathrm{a}\)
\(\begin{aligned}
\therefore \quad \mathrm{a}=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 173}{1.73} & =400 \mathrm{pm} \\
& =400 \times 10^{-10} \mathrm{~cm} \\
& =4.00 \times 10^{-8} \mathrm{~cm}
\end{aligned}\)
\(\begin{aligned}
\therefore \quad \mathrm{a}=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 173}{1.73} & =400 \mathrm{pm} \\
& =400 \times 10^{-10} \mathrm{~cm} \\
& =4.00 \times 10^{-8} \mathrm{~cm}
\end{aligned}\)
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