MHT CET · Chemistry · Solid State
Calculate the edge length of bcc unit cell if radius of metal atom is \(227 \mathrm{pm}\).
- A \(4.54 \times 10^{-8} \mathrm{~cm}\)
- B \(5.24 \times 10^{-8} \mathrm{~cm}\)
- C \(6.42 \times 10^{-8} \mathrm{~cm}\)
- D \(1.135 \times 10^{-8} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(5.24 \times 10^{-8} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
For bcc unit cell, \(r=\frac{\sqrt{3}}{4} \mathrm{a}\)
\(\begin{aligned}
\therefore \quad \mathrm{a}=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 227}{1.73} & =524.85 \mathrm{pm} \\
& =524.85 \times 10^{-10} \mathrm{~cm} \\
& =5.24 \times 10^{-8} \mathrm{~cm}
\end{aligned}\)
\(\begin{aligned}
\therefore \quad \mathrm{a}=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 227}{1.73} & =524.85 \mathrm{pm} \\
& =524.85 \times 10^{-10} \mathrm{~cm} \\
& =5.24 \times 10^{-8} \mathrm{~cm}
\end{aligned}\)
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