MHT CET · Chemistry · Solid State
Calculate the density of metal having volume of unit cell \(64 \times 10^{-24} \mathrm{~cm}^3\) and molar mass of metal \(192 \mathrm{~g} \mathrm{~mol}^{-1}\) containing 4 particles in unit cell.
- A \(16.00 \mathrm{~g} \mathrm{~cm}^{-3}\)
- B \(19.93 \mathrm{~g} \mathrm{~cm}^{-3}\)
- C \(14.92 \mathrm{~g} \mathrm{~cm}^{-3}\)
- D \(18.00 \mathrm{~g} \mathrm{~cm}^{-3}\)
Answer & Solution
Correct Answer
(B) \(19.93 \mathrm{~g} \mathrm{~cm}^{-3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{d}=\frac{4 \times 192}{64 \times 10^{-24} \times 602 \times 10^{23}} \\ & =19.93 \mathrm{~g} \mathrm{~cm}^{-3}\end{aligned}\)
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