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MHT CET · Chemistry · Solid State

Calculate the density of metal having molar mass \(210 \mathrm{~g} \mathrm{~mol}^{-1}\) that forms simple cubic unit cell. \(\left(\mathrm{a}^3 \cdot \mathrm{N}_{\mathrm{A}}=21.5 \mathrm{~cm}^3 \mathrm{~mol}^{-1}\right)\)

  1. A \(9.77 \mathrm{~g} \mathrm{~cm}^{-3}\)
  2. B \(7.15 \mathrm{~g} \mathrm{~cm}^{-3}\)
  3. C \(8.12 \mathrm{~g} \mathrm{~cm}^{-3}\)
  4. D \(6.94 \mathrm{~g} \mathrm{~cm}^{-3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(9.77 \mathrm{~g} \mathrm{~cm}^{-3}\)

Step-by-step Solution

Detailed explanation

For simple cubic unit cell, \(\mathrm{n}=1\).
Density \((\rho)=\frac{\mathrm{nM}}{\mathrm{a}^3 \mathrm{~N}_{\mathrm{A}}}=\frac{1 \times 210}{21.5}=9.77 \mathrm{~g} \mathrm{~cm}^{-3}\)