MHT CET · Chemistry · Solid State
Calculate the density of an element having molar mass \(27 \mathrm{~g} \mathrm{~mol}^{-1}\) that forms fcc unit cell. \(\left[\mathrm{a}^3 \cdot \mathrm{N}_{\mathrm{A}}=38.5 \mathrm{~cm}^3 \mathrm{~mol}^{-1}\right]\)
- A \(2.8 \mathrm{~g} \mathrm{~cm}^{-3}\)
- B \(2.1 \mathrm{~g} \mathrm{~cm}^{-3}\)
- C \(3.5 \mathrm{~g} \mathrm{~cm}^{-3}\)
- D \(4.1 \mathrm{~g} \mathrm{~cm}^{-3}\)
Answer & Solution
Correct Answer
(A) \(2.8 \mathrm{~g} \mathrm{~cm}^{-3}\)
Step-by-step Solution
Detailed explanation
Density, \(\rho=\frac{M \text { n }}{a^3 N_A}\)
\(
\begin{aligned}
\rho & =\frac{27 \mathrm{~g} \mathrm{~mol}^{-1} \times 4 \text { atom }}{38.5 \mathrm{~cm}^3 \mathrm{~mol}^{-1}} \\
& =2.8 \mathrm{~g} \mathrm{~cm}^{-3}
\end{aligned}
\)
\(
\begin{aligned}
\rho & =\frac{27 \mathrm{~g} \mathrm{~mol}^{-1} \times 4 \text { atom }}{38.5 \mathrm{~cm}^3 \mathrm{~mol}^{-1}} \\
& =2.8 \mathrm{~g} \mathrm{~cm}^{-3}
\end{aligned}
\)
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