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MHT CET · Chemistry · Chemical Equilibrium

Calculate the degree of dissociation of \(0.01 \mathrm{M}\) acetic acid at \(25^{\circ} \mathrm{C}\left[\Lambda_{\mathrm{c}}=15.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\right.\) and \(\left.\Lambda_0=300 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\right]\)

  1. A \(0.042\)
  2. B \(0.035\)
  3. C \(0.025\)
  4. D \(0.05\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0.05\)

Step-by-step Solution

Detailed explanation

Degree of dissociation \((\alpha)=\frac{\Lambda_c}{\Lambda_0}=\frac{15.0}{300}=0.05\)