MHT CET · Chemistry · Solutions
Calculate the cryoscopic constant when 0.8 gram nonvolatile solute with molar mass \(64 \mathrm{~g} \mathrm{~mol}^{-1}\) dissolved in 43 gram solvent lowers the freezing point by \(0.34 \mathrm{~K}\).
- A \(2.5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
- B \(2.0 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
- C \(0.85 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
- D \(1.17 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(D) \(1.17 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{k}_{\mathrm{f}} \mathrm{m} \\ & 0.34=\mathrm{k}_{\mathrm{f}} \times \frac{0.8}{64} \times \frac{1000}{43} \\ & \mathrm{k}_{\mathrm{f}}=1.169 \sim 1.17\end{aligned}\)
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