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MHT CET · Chemistry · Electrochemistry

Calculate the conductivity of \(0.02 \mathrm{M}\) electrolyte solution if its molar conductivity is \(407.2 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) ?

  1. A \(8.144 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
  2. B \(4.072 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
  3. C \(7.15 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
  4. D \(6.055 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(8.144 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \Lambda_{\mathrm{m}} & =\frac{1000 \mathrm{k}}{\mathrm{c}} \\ \mathrm{k} & =\frac{\Lambda_{\mathrm{m}} \times \mathrm{c}}{1000}=\frac{407.2 \times 0.02}{1000} \\ & =8.144 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\end{aligned}\)