MHT CET · Chemistry · Electrochemistry
Calculate the conductivity of \(0.02 \mathrm{M}\) electrolyte solution if its molar conductivity is \(407.2 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) ?
- A \(8.144 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
- B \(4.072 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
- C \(7.15 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
- D \(6.055 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(A) \(8.144 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \Lambda_{\mathrm{m}} & =\frac{1000 \mathrm{k}}{\mathrm{c}} \\ \mathrm{k} & =\frac{\Lambda_{\mathrm{m}} \times \mathrm{c}}{1000}=\frac{407.2 \times 0.02}{1000} \\ & =8.144 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\end{aligned}\)
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