MHT CET · Chemistry · Ionic Equilibrium
Calculate the concentration of weak monobasic acid if its degree of dissociation and dissociation constant are \(5.0 \times 10^{-4}\) and \(5.0 \times 10^{-9}\) respectively.
- A 0.1 M
- B \(0.02 \mathrm{M}\)
- C \( 0.03 \mathrm{M}\)
- D \(0.04 \mathrm{M}\)
Answer & Solution
Correct Answer
(B) \(0.02 \mathrm{M}\)
Step-by-step Solution
Detailed explanation
For a weak monobasic acid,
\(\mathrm{K}_{\mathrm{a}}=\alpha^2 \mathrm{c}\)
\(\therefore \mathrm{c}=\frac{\mathrm{K}_{\mathrm{a}}}{\alpha^2}=\frac{5.0 \times 10^{-9}}{\left(5.0 \times 10^{-4}\right)^2}=\frac{1 \times 10^{-9}}{5 \times 10^{-8}}\) \(=0.02 \mathrm{M}\)
\(\mathrm{K}_{\mathrm{a}}=\alpha^2 \mathrm{c}\)
\(\therefore \mathrm{c}=\frac{\mathrm{K}_{\mathrm{a}}}{\alpha^2}=\frac{5.0 \times 10^{-9}}{\left(5.0 \times 10^{-4}\right)^2}=\frac{1 \times 10^{-9}}{5 \times 10^{-8}}\) \(=0.02 \mathrm{M}\)
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