MHT CET · Chemistry · Ionic Equilibrium
Calculate the concentration of \(\mathrm{H}^{+}\)ions in a solution if \(\mathrm{pOH}\) is 11 .
- A \(10^{-11} \mathrm{M}\)
- B \(10^{-8} \mathrm{M}\)
- C \(10^{-6} \mathrm{M}\)
- D \(10^{-3} \mathrm{M}\)
Answer & Solution
Correct Answer
(D) \(10^{-3} \mathrm{M}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \mathrm{pOH}=11 \\ & \mathrm{pH}+\mathrm{pOH}=14 \\ \therefore \quad & \mathrm{pH}=14-\mathrm{pOH}=14-11=3 \\ & \mathrm{pH}=-\log _{10}\left[\mathrm{H}^{+}\right] \\ \therefore \quad & {\left[\mathrm{H}^{+}\right]=10^{-\mathrm{pH}^{-}}=10^{-3} \mathrm{M}}\end{array}\)
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