MHT CET · Chemistry · Solutions
Calculate the amount of solute dissolved in 612 grams of water at \(30^{\circ} \mathrm{C}\) if molar mass of solute is \(342 \mathrm{~g} \mathrm{~mol}^{-1}\) (Relative vapour pressure lowering is 0.025 and molar mass of water \(18 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A 142.5 gram
- B 270.6 gram
- C 240.2 gram
- D 290.7 gram
Answer & Solution
Correct Answer
(D) 290.7 gram
Step-by-step Solution
Detailed explanation
\(\frac{\Delta P}{P_A^{\circ}}=x_B \simeq \frac{n_B}{n_A}\)
\(\frac{W_B}{342} \times \frac{18}{612}=0.025\)
\(W_B=290.7\)
\(\frac{W_B}{342} \times \frac{18}{612}=0.025\)
\(W_B=290.7\)
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