MHT CET · Chemistry · Solutions
Calculate the amount of solute dissolved in \(3 \mathrm{dm}^3\) water having osmotic pressure \(0.3 \mathrm{~atm}\) at \(300 \mathrm{~K}\)
(Molar mass of solute \(=108 \mathrm{~g} \mathrm{~mol}^{-1}, R=0.0821 \mathrm{~atm} \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\) )
- A 4.51 gram
- B 3.95 gram
- C 3.45 gram
- D 5.26 gram
Answer & Solution
Correct Answer
(B) 3.95 gram
Step-by-step Solution
Detailed explanation
Osmotic pressure
\(\begin{aligned} & \pi=i C R T \\ & 0.3=1 \times \frac{W}{108} \times \frac{1}{3} \times 0.0821 \times 300 \\ & W=3.95 \mathrm{gm}\end{aligned}\)
\(\begin{aligned} & \pi=i C R T \\ & 0.3=1 \times \frac{W}{108} \times \frac{1}{3} \times 0.0821 \times 300 \\ & W=3.95 \mathrm{gm}\end{aligned}\)
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