MHT CET · Chemistry · Solutions
Calculate the amount of solute dissolved in 160 gram solvent that boils at \(85^{\circ} \mathrm{C}\). the molar mass of solute is \(120 \mathrm{~g} \mathrm{~mol}^{-1}\).
\(\left(\mathrm{K}_{\mathrm{b}}\right.\) for solvent \(=2.7^{\circ} \mathrm{C} \mathrm{kg} \mathrm{mol}^{-1}\) and boiling point of solvent \(\left.=76^{\circ} \mathrm{C}\right)\)
- A 64 gram
- B 42 gram
- C 50 gram
- D 60 gram
Answer & Solution
Correct Answer
(A) 64 gram
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{T}_{\mathrm{b}}=(85-76)=2.7 \times \frac{\mathrm{W}_{\mathrm{B}}}{120} \times \frac{1000}{160}\)
\(\mathrm{W}_{\mathrm{B}}=64 \mathrm{~g}\)
\(\mathrm{W}_{\mathrm{B}}=64 \mathrm{~g}\)
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