MHT CET · Chemistry · Solutions

Calculate osmotic pressure exerted by a solution containing \(0.822 \mathrm{~g}\) of solute in \(300 \mathrm{~mL}\) of water at \(300 \mathrm{~K}\).
(Molar mass of solute \(=340 \mathrm{~mol}^{-1}, \mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) )

A 0.5 atm
B 0.2 atm
C 0.1 atm
D 0.4 atm

Verified Solution

Answer & Solution

Correct Answer

(B) 0.2 atm

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \pi=\mathrm{CRT} \\ & \mathrm{C}=\frac{\text { moles of solute }}{\text { volumeof solution }(\mathrm{ml})} \times 1000 \\ & =\frac{0.822 / 340}{300} \times 1000 \\ & =0.008 \\ & \pi=0.008 \times 0.0821 \times 300 \\ & \pi=0.2 \mathrm{~atm}\end{aligned}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Calculate osmotic pressure exerted by a solution containing \(0.822 \mathrm{~g}\) of solute in \(300 \mathrm{~mL}\) of water at \(300 \mathrm{~K}\).(Molar mass of solute \(=340 \mathrm{~mol}^{-1}, \mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) )

Step-by-step Solution

Calculate osmotic pressure exerted by a solution containing \(0.822 \mathrm{~g}\) of solute in \(300 \mathrm{~mL}\) of water at \(300 \mathrm{~K}\).
(Molar mass of solute \(=340 \mathrm{~mol}^{-1}, \mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) )