MHT CET · Chemistry · Some Basic Concepts of Chemistry
Calculate number of moles present in \(9.10 \times 10^{-2} \mathrm{~kg}\) of water.
- A 0.9
- B 1.8
- C 3
- D 5
Answer & Solution
Correct Answer
(D) 5
Step-by-step Solution
Detailed explanation
Molar mass of water \(\left(\mathrm{H}_2 \mathrm{O}\right)=18 \times 10^{-3} \mathrm{~kg} \mathrm{~mol}^{-1}\)
\(\therefore \quad\) Moles of \(\mathrm{H}_2 \mathrm{O}=\frac{9.10 \times 10^{-2}}{18 \times 10^{-3}}=5.05 \approx 5.0 \mathrm{~mol}\)
\(\therefore \quad\) Moles of \(\mathrm{H}_2 \mathrm{O}=\frac{9.10 \times 10^{-2}}{18 \times 10^{-3}}=5.05 \approx 5.0 \mathrm{~mol}\)
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