MHT CET · Chemistry · Solutions
Calculate molar mass of nonvolatile solute if a solution containing 0.35 g solute in 100 g .water has boiling point elevation 0.01 K \(\left[\mathrm{K}_{\mathrm{b}}=0.50 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right.\) ]
- A \(265 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(175 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(105 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(195 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(B) \(175 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \mathrm{m}=\mathrm{K}_{\mathrm{b}} \frac{1000 \mathrm{~W}_2}{\mathrm{~W}_1 \mathrm{M}_2} \\ & \mathrm{M}_2=\frac{1000 \times 0.50 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1} \times 0.35 \mathrm{~g}}{100 \mathrm{~g} \times 0.01 \mathrm{~K}} \\ & \mathrm{M}_1=175 \mathrm{~g} \mathrm{~mol}^{-1}\end{aligned}\)
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