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MHT CET · Chemistry · Solutions

Calculate molar mass of a solute at 300 K if 400 mg of it is dissolved in 300 mL of water exerts osmotic pressure of 0.2 atm .
\(\left(\mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)

  1. A \(90 \mathrm{~g} \mathrm{~mol}^{-1}\)
  2. B \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
  3. C \(164 \mathrm{~g} \mathrm{~mol}^{-1}\)
  4. D \(180 \mathrm{~g} \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(164 \mathrm{~g} \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{M}_2 =\frac{\mathrm{W}_2 \mathrm{RT}}{\pi \mathrm{V}} \)
\( =\frac{0.4 \mathrm{~g} \times 0.0821 \mathrm{dm}^3 \mathrm{atmK}^{-1} \mathrm{~mol}^{-1} \times 300 \mathrm{~K}}{0.2 \mathrm{~atm} \times 0.3 \mathrm{dm}^3} \)
\( =164.2 \mathrm{~g} \mathrm{~mol}^{-1} \approx 164 \mathrm{~g} \mathrm{~mol}^{-1}\)