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MHT CET · Chemistry · Electrochemistry

Calculate molar conductivity at infinite dilution for \(\mathrm{NaBr}\) if molar conductivity at infinite dilution for \(\mathrm{NaCl}, \mathrm{KBr}\) and \(\mathrm{KCl}\) are 126, 152 and \(150 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) respectively

  1. A \(128 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  2. B \(302 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  3. C \(278 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  4. D \(176 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(128 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \wedge{ }^0 \mathrm{NaBr}=\wedge{ }^0 \mathrm{NaCl}+\wedge^{\circ} \mathrm{KBr}-\wedge^{\circ} \mathrm{KCl} \\ & =126+152-150 \\ & =128 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mole}^{-1}\end{aligned}\)