MHT CET · Chemistry · Electrochemistry
Calculate mass of a divalent metal produced at cathode by passing \(5 \mathrm{amp}\) current through its salt solution for 100 minutes. (Molar mas of metal \(=x\) )
- A \(\frac{193}{30} x\)
- B \(\frac{193}{15} x\)
- C \(\frac{15}{193} x\)
- D \(\frac{30}{193} x\)
Answer & Solution
Correct Answer
(D) \(\frac{30}{193} x\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{W}=\frac{\mathrm{E}}{\mathrm{F}} \mathrm{It}=\frac{\mathrm{X}}{2 \times 96500} \times 5 \times 100 \times 60 \\ & =\frac{\mathrm{x} \times 5 \times 30}{965} \\ & \mathrm{~W}=\frac{30 \mathrm{x}}{193}\end{aligned}\)
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