MHT CET · Chemistry · Some Basic Concepts of Chemistry
Calculate mass in kg of \(4.48 \mathrm{dm}^3\) carbon dioxide at STP.
- A \(2.2 \times 10^{-3}\)
- B \(4.4 \times 10^{-3}\)
- C \(6.6 \times 10^{-3}\)
- D \(8.8 \times 10^{-3}\)
Answer & Solution
Correct Answer
(D) \(8.8 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
\(22.4 \mathrm{dm}^3 \mathrm{CO}_2 \text { at } \mathrm{STP} =1 \mathrm{~mol}=44 \mathrm{~g} \text { of } \mathrm{CO}_2 \)
\( \therefore 4.48 \mathrm{dm}^3 \text { of } \mathrm{CO}_2 \text { at } \mathrm{STP} =\frac{44 \mathrm{~g} \times 4.48 \mathrm{dm}^3}{22.4 \mathrm{dm}^3} \)
\( =8.8 \mathrm{~g} \text { of } \mathrm{CO}_2 \)
\( =8.8 \times 10^{-3}{\mathrm{~kg~} \mathrm{~of~} \mathrm{CO}_2}^2\)
\( \therefore 4.48 \mathrm{dm}^3 \text { of } \mathrm{CO}_2 \text { at } \mathrm{STP} =\frac{44 \mathrm{~g} \times 4.48 \mathrm{dm}^3}{22.4 \mathrm{dm}^3} \)
\( =8.8 \mathrm{~g} \text { of } \mathrm{CO}_2 \)
\( =8.8 \times 10^{-3}{\mathrm{~kg~} \mathrm{~of~} \mathrm{CO}_2}^2\)
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