MHT CET · Chemistry · Ionic Equilibrium
Calculate \(\left[\mathrm{H}_3 \mathrm{O}^{+}\right]\)in 0.02 M solution of monobasic acid if dissociation constant is \(1.8 \times 10^{-5}\).
- A \(3.0 \times 10^{-4} \mathrm{M}\)
- B \(6.0 \times 10^{-4} \mathrm{M}\)
- C \(2.0 \times 10^{-4} \mathrm{M}\)
- D \(4.0 \times 10^{-4} \mathrm{M}\)
Answer & Solution
Correct Answer
(B) \(6.0 \times 10^{-4} \mathrm{M}\)
Step-by-step Solution
Detailed explanation
For a weak monobasic acid,
\(\therefore \alpha=\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{c}}}=\sqrt{\frac{1.8 \times 10^{-5}}{0.02}}=3 \times 10^{-2}\)
\(\left[\text H _3 O ^{+}\right]=\alpha c =3 \times 10^{-2} \times 0.02\) \(=6.0 \times 10^{-4}\text M\)
\(\therefore \alpha=\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{c}}}=\sqrt{\frac{1.8 \times 10^{-5}}{0.02}}=3 \times 10^{-2}\)
\(\left[\text H _3 O ^{+}\right]=\alpha c =3 \times 10^{-2} \times 0.02\) \(=6.0 \times 10^{-4}\text M\)
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