MHT CET · Chemistry · Solutions
Calculate freezing point of a 0.05 molal aqueous solution of a nonelectrolyte?
- A 186 K
- B 272.9 K
- C 93 K
- D 278 K
Answer & Solution
Correct Answer
(B) 272.9 K
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
\Delta T_f & =K_f \times m \\
& =1.86 \times 0.02 \\
& =0.093 \mathrm{~K}
\end{aligned}\)
or \(T_f-T=0.093\)
\(\begin{aligned}
T & =273-0.093 \\
& =272.9 \mathrm{~K}
\end{aligned}\)
\Delta T_f & =K_f \times m \\
& =1.86 \times 0.02 \\
& =0.093 \mathrm{~K}
\end{aligned}\)
or \(T_f-T=0.093\)
\(\begin{aligned}
T & =273-0.093 \\
& =272.9 \mathrm{~K}
\end{aligned}\)
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