MHT CET · Chemistry · Electrochemistry
Calculate \(\mathrm{E}_{\text {cell }}^{\circ}\) in which following reaction occurs. \(\mathrm{Mg}_{(\mathrm{s})}+2 \mathrm{Ag}_{(1 \mathrm{M})}^{+} \rightarrow \mathrm{Mg}_{(1 \mathrm{M})}^{++}+2 \mathrm{Ag}_{(\mathrm{s})}\) if \(\mathrm{E}_{\mathrm{Ag}}^{\circ}=0.8 \mathrm{~V}\) and \(\mathrm{E}_{\mathrm{Mg}}^{\circ}=-2.37 \mathrm{~V}\)
- A \(-3.17 \mathrm{~V}\)
- B \(3.17 \mathrm{~V}\)
- C \(-1.57 \mathrm{~V}\)
- D \(1.57 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(3.17 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
For the given cell reaction, anode is \(\mathrm{Mg}\) and cathode is Ag.
\(\begin{aligned}
\mathrm{E}_{\text {cell }}^0 & =\mathrm{E}_{\text {cathode }}^0-\mathrm{E}_{\text {anode }}^0 \\
& =0.8-(-2.37) \\
& =3.17 \mathrm{~V}
\end{aligned}\)
\(\begin{aligned}
\mathrm{E}_{\text {cell }}^0 & =\mathrm{E}_{\text {cathode }}^0-\mathrm{E}_{\text {anode }}^0 \\
& =0.8-(-2.37) \\
& =3.17 \mathrm{~V}
\end{aligned}\)
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