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MHT CET · Chemistry · Electrochemistry

Calculate \(\mathrm{E}_{\text {cell }}^{\circ}\) in which following reaction occurs. \(\mathrm{Mg}_{(\mathrm{s})}+2 \mathrm{Ag}_{(1 \mathrm{M})}^{+} \rightarrow \mathrm{Mg}_{(1 \mathrm{M})}^{++}+2 \mathrm{Ag}_{(\mathrm{s})}\) if \(\mathrm{E}_{\mathrm{Ag}}^{\circ}=0.8 \mathrm{~V}\) and \(\mathrm{E}_{\mathrm{Mg}}^{\circ}=-2.37 \mathrm{~V}\)

  1. A \(-3.17 \mathrm{~V}\)
  2. B \(3.17 \mathrm{~V}\)
  3. C \(-1.57 \mathrm{~V}\)
  4. D \(1.57 \mathrm{~V}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3.17 \mathrm{~V}\)

Step-by-step Solution

Detailed explanation

For the given cell reaction, anode is \(\mathrm{Mg}\) and cathode is Ag.
\(\begin{aligned}
\mathrm{E}_{\text {cell }}^0 & =\mathrm{E}_{\text {cathode }}^0-\mathrm{E}_{\text {anode }}^0 \\
& =0.8-(-2.37) \\
& =3.17 \mathrm{~V}
\end{aligned}\)