MHT CET · Chemistry · Electrochemistry
Calculate dissociation constant of \(0.001 \mathrm{M}\) weak monoacidic base undergoing \(2 \%\) dissociation.
- A \(4 \times 10^{-7}\)
- B \(2 \times 10^{-6}\)
- C \(2 \times 10^{-7}\)
- D \(1 \times 10^{-7}\)
Answer & Solution
Correct Answer
(A) \(4 \times 10^{-7}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \alpha=\frac{\text { Percent dissociation }}{100}=\frac{2}{100}=0.02 \\ & K_a=\alpha^2 c=(0.02)^2 \times 0.001=4 \times 10^{-7}\end{aligned}\)
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