MHT CET · Chemistry · Hydrogen
Calculate \(\%\) by mass of a \(\mathrm{H}_2 \mathrm{O}_2\) solution that is 67.2% by volume.
- A \(13.60 \%\) by mass
- B \(20.40 \%\) by mass
- C \(22.44 \%\) by mass
- D \(17 \cdot 60 \%\) by mass
Answer & Solution
Correct Answer
(B) \(20.40 \%\) by mass
Step-by-step Solution
Detailed explanation
\(M = \frac{67.2}{11.2} = 6 \mathrm{M}\) \(\% \text{ by mass} = \frac{6 \mathrm{mol/L} \times 34.0 \mathrm{g/mol}}{1.0 \mathrm{g/mL} \times 1000 \mathrm{mL/L}} \times 100\)
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