ExamBro
ExamBro
MHT CET · Chemistry · Redox Reactions

Calculate amount of methane formed by liberation of \(149.6 \mathrm{~kJ}\) of heat using following equation.
\( \mathrm{C}_{(\mathrm{s})}+2 \mathrm{H}_{2(\mathrm{~g})} \longrightarrow \mathrm{CH}_{4(\mathrm{~g})} \quad \Delta \mathrm{H}\) \(=-74.8 \mathrm{~kJ} / \mathrm{mol} \)

  1. A \(16 \mathrm{~g}\)
  2. B \(24 \mathrm{~g}\)
  3. C \(32 \mathrm{~g}\)
  4. D \(48 \mathrm{~g}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(32 \mathrm{~g}\)

Step-by-step Solution

Detailed explanation

According to the given reaction, \(74.8 \mathrm{~kJ}\) of heat is evolved when 1 mol of methane is formed.
\(
\begin{aligned}
& 74.8 \mathrm{~kJ} \equiv 1 \mathrm{~mol} \mathrm{CH}_4=16 \mathrm{~g} \mathrm{CH}_4 \\
& 149.6 \mathrm{~kJ} \equiv x \mathrm{~g} \mathrm{CH}_4 \\
& x=\frac{149.6 \times 16}{74.8}=32 \mathrm{~g}
\end{aligned}
\)