MHT CET · Chemistry · Thermodynamics (C)
An ideal gas expands from \(1 \times 10^{-3} \mathrm{~m}^{3}\) to \(1 \times 10^{-2} \mathrm{~m}^{3}\) at \(300 \mathrm{~K}\) against a constant external pressure of \(1 \times 10^{5} \mathrm{~nm}^{-2}\), work done is
- A \(-9 \times 10^{2} \mathrm{~J}\)
- B \(-9 \times 10^{3} \mathrm{~J}\)
- C \(-0.7 \times 10^{3} \mathrm{~J}\)
- D \(-1 \times 10^{3} \mathrm{~J}\)(a)
Answer & Solution
Correct Answer
(A) \(-9 \times 10^{2} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} V_{1} &=1 \times 10^{-3} \mathrm{~m}^{3}=0.001 \mathrm{~m}^{3} \\ V_{2} &=1 \times 10^{-2} \mathrm{~m}^{3}=0.01 \mathrm{~m}^{3} \\ P_{\mathrm{ex}} &=1 \times 10^{5} \mathrm{Nm}^{-2} \\ W &=-P_{\mathrm{ex}}\left(V_{2}-V_{1}\right)=-1 \times 10^{5}(0.01-0.001) \\ &=-0.009 \times 10^{5} \\ W &=-9 \times 10^{2} \mathrm{~J} \end{aligned}\)
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