MHT CET · Chemistry · Thermodynamics (C)
An ideal gas expands by performing \(200 \mathrm{~J}\) of work, during this internal energy increases by \(432 \mathrm{~J}\). What is enthalpy change?
- A \(200 \mathrm{J}\)
- B \(232 \mathrm{J}\)
- C \(432 \mathrm{J}\)
- D \(632 \mathrm{J}\)
Answer & Solution
Correct Answer
(D) \(632 \mathrm{J}\)
Step-by-step Solution
Detailed explanation
Assuming constant pressure,
\(\Delta \mathrm{H}=\Delta \mathrm{U}+\mathrm{P}_{\mathrm{ext}} \Delta \mathrm{V}=\Delta \mathrm{U}-\mathrm{W}\)
Work done \((\mathrm{W})=-200 \mathrm{~J}\) (for expansion of a gas)
\(\begin{aligned}
& \Delta \mathrm{U}=+432 \mathrm{~J} \\
& \Delta \mathrm{H}=\Delta \mathrm{U}-\mathrm{W}=+432-(-200)=+632 \mathrm{~J}
\end{aligned}\)
\(\Delta \mathrm{H}=\Delta \mathrm{U}+\mathrm{P}_{\mathrm{ext}} \Delta \mathrm{V}=\Delta \mathrm{U}-\mathrm{W}\)
Work done \((\mathrm{W})=-200 \mathrm{~J}\) (for expansion of a gas)
\(\begin{aligned}
& \Delta \mathrm{U}=+432 \mathrm{~J} \\
& \Delta \mathrm{H}=\Delta \mathrm{U}-\mathrm{W}=+432-(-200)=+632 \mathrm{~J}
\end{aligned}\)
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