MHT CET · Chemistry · Solid State
An element with simple cubic close structure has edge length of unit cell \(3.86 Å\). What is the radius of atom?
- A \(5.79 \times 10^{-8} \mathrm{~cm}\)
- B \(1.93 \times 10^{-8} \mathrm{~cm}\)
- C \(3.86 \times 10^{-8} \mathrm{~cm}\)
- D \(2.43 \times 10^{-8} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(1.93 \times 10^{-8} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
In simple cubic close structure
\(
\begin{aligned}
& \mathrm{a}=2 \mathrm{r} \\
& \mathrm{r}=\frac{\mathrm{a}}{2}=\frac{3.86}{2}=1.93 Å \\
& \mathrm{r}=1.93 \times 10^{-8} \mathrm{~cm} \\
& \left(1 \mathrm{~A}^{\circ}=10^{-10} \mathrm{~m}=10^{-8} \mathrm{~cm}\right)
\end{aligned}
\)
\(
\begin{aligned}
& \mathrm{a}=2 \mathrm{r} \\
& \mathrm{r}=\frac{\mathrm{a}}{2}=\frac{3.86}{2}=1.93 Å \\
& \mathrm{r}=1.93 \times 10^{-8} \mathrm{~cm} \\
& \left(1 \mathrm{~A}^{\circ}=10^{-10} \mathrm{~m}=10^{-8} \mathrm{~cm}\right)
\end{aligned}
\)
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