MHT CET · Chemistry · Solid State
An element crystallises in bcc type having atomic radius \(1 \cdot 33 \times 10^{-8} \mathrm{~cm}\), the edge length of unit cell will be
- A \(2 \cdot 17 \times 10^{-8} \mathrm{~cm}\)
- B \(2 \cdot 66 \times 10^{-8} \mathrm{~cm}\)
- C \(4.08 \times 10^{-8} \mathrm{~cm}\)
- D \(3 \cdot 07 \times 10^{-8} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(D) \(3 \cdot 07 \times 10^{-8} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
For bcc crystal, \(\quad \mathrm{r}=\frac{\sqrt{3}}{4} \mathrm{a}\)
\(\therefore \quad a=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 1.33 \times 10^{-8} \mathrm{~cm}}{1.732}\)
\(\therefore \quad a=3.07 \times 10^{-8} \mathrm{~cm} .\)
\(\therefore \quad a=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 1.33 \times 10^{-8} \mathrm{~cm}}{1.732}\)
\(\therefore \quad a=3.07 \times 10^{-8} \mathrm{~cm} .\)
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