MHT CET · Chemistry · Solid State
An element crystallises in bcc type crystal structure with edge length of unit cell \(300 \mathrm{pm} .\) Calculate radius of element?
- A \(2 \cdot 299 \times 10^{-8} \mathrm{~cm}\)
- B \(1 \cdot 299 \times 10^{-8} \mathrm{~cm}\)
- C \(6 \cdot 920 \times 10^{-8} \mathrm{~cm}\)
- D \(1 \cdot 440 \times 10^{-8} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(1 \cdot 299 \times 10^{-8} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
\(a=300 \mathrm{pm}=3 \times 10^{-8} \mathrm{~cm}\)
For bcc unit cell, \(r=\frac{\sqrt{3} a}{4}\)
\(\therefore r=\frac{1.732 \times 3 \times 10^{-8} \mathrm{~cm}}{4}=1.299 \times 10^{-8} \mathrm{~cm}\)
For bcc unit cell, \(r=\frac{\sqrt{3} a}{4}\)
\(\therefore r=\frac{1.732 \times 3 \times 10^{-8} \mathrm{~cm}}{4}=1.299 \times 10^{-8} \mathrm{~cm}\)
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