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MHT CET · Chemistry · Solid State

An element crystallises in bcc type crystal structure with edge length of unit cell \(300 \mathrm{pm} .\) Calculate radius of element?

  1. A \(2 \cdot 299 \times 10^{-8} \mathrm{~cm}\)
  2. B \(1 \cdot 299 \times 10^{-8} \mathrm{~cm}\)
  3. C \(6 \cdot 920 \times 10^{-8} \mathrm{~cm}\)
  4. D \(1 \cdot 440 \times 10^{-8} \mathrm{~cm}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1 \cdot 299 \times 10^{-8} \mathrm{~cm}\)

Step-by-step Solution

Detailed explanation

\(a=300 \mathrm{pm}=3 \times 10^{-8} \mathrm{~cm}\)
For bcc unit cell, \(r=\frac{\sqrt{3} a}{4}\)
\(\therefore r=\frac{1.732 \times 3 \times 10^{-8} \mathrm{~cm}}{4}=1.299 \times 10^{-8} \mathrm{~cm}\)