MHT CET · Chemistry · Solutions
An aqueous solution of urea containing \(18 \mathrm{~g}\) urea in \(1500 \mathrm{~cm}^{3}\) of the solution has a density equal to \(1.052\). If the molecular weight of urea is 60, the molality of the solution is
- A \(0.200\)
- B \(0.192\)
- C \(0.100\)
- D \(1.200\)
Answer & Solution
Correct Answer
(B) \(0.192\)
Step-by-step Solution
Detailed explanation
\(
1500 \mathrm{cc} \text { . solution }=1500 \times 1.052 \mathrm{~g}
\)
\(=1578 \mathrm{~g}\)
Weight of solvent \(=1560 \mathrm{~g}\)
Weight of solute \(=18 \mathrm{~g}\)
Molality \(=\frac{\text { weight of solute }}{\text { molecular weight of solute } \times}\)
weight of solvent in \(\mathrm{kg}\)
\(=\frac{18 \times 1000}{60 \times 1560}\)
\(=0.192 \mathrm{~m}\)
1500 \mathrm{cc} \text { . solution }=1500 \times 1.052 \mathrm{~g}
\)
\(=1578 \mathrm{~g}\)
Weight of solvent \(=1560 \mathrm{~g}\)
Weight of solute \(=18 \mathrm{~g}\)
Molality \(=\frac{\text { weight of solute }}{\text { molecular weight of solute } \times}\)
weight of solvent in \(\mathrm{kg}\)
\(=\frac{18 \times 1000}{60 \times 1560}\)
\(=0.192 \mathrm{~m}\)
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