MHT CET · Chemistry · Ionic Equilibrium
An acid solution of \(\mathrm{pH}=6\) is diluted 1000 times, the pH of the final solution becomes
- A \(6.01\)
- B 9
- C \(3.5\)
- D \(6.99\)
Answer & Solution
Correct Answer
(D) \(6.99\)
Step-by-step Solution
Detailed explanation
\(\because \mathrm{pH}=6\)
\(\therefore\)
\(\left[\mathrm{H}^{+}\right]=10^{-6} \mathrm{M}\)
After dilution \(\left[\mathrm{H}^{+}\right]=\frac{10^{-6}}{1000}=10^{-9} \mathrm{M}\)
\(\therefore\left[\mathrm{H}^{+}\right]\) from \(\mathrm{H}_{2} \mathrm{O}\) cannot be neglected.
Total \(\left[\mathrm{H}^{+}\right]=10^{-9}+10^{-7}\)
\(\begin{aligned} &=10^{-7}\left(10^{-2}+1\right) \\ &=10^{-7}(1.01) \\ \mathrm{pH} &=-\log \left(1.01 \times 10^{-7}\right) \\ &=7-0.0043 \\ &=6.9957 \end{aligned}\)
\(\therefore\)
\(\left[\mathrm{H}^{+}\right]=10^{-6} \mathrm{M}\)
After dilution \(\left[\mathrm{H}^{+}\right]=\frac{10^{-6}}{1000}=10^{-9} \mathrm{M}\)
\(\therefore\left[\mathrm{H}^{+}\right]\) from \(\mathrm{H}_{2} \mathrm{O}\) cannot be neglected.
Total \(\left[\mathrm{H}^{+}\right]=10^{-9}+10^{-7}\)
\(\begin{aligned} &=10^{-7}\left(10^{-2}+1\right) \\ &=10^{-7}(1.01) \\ \mathrm{pH} &=-\log \left(1.01 \times 10^{-7}\right) \\ &=7-0.0043 \\ &=6.9957 \end{aligned}\)
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