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MHT CET · Chemistry · Chemical Equilibrium

Achemical reaction takes places in two steps as follows:
(i) \(NO _2 Cl ( g ) \xrightarrow{K_1} NO 2(g)+ Cl ( g )\)
(ii) \(NO _2 Cl ( g )+ Cl ( g ) \xrightarrow{K_2} NO _2(g)+ Cl _2(g)\)
Identify the reaction intermediate.

  1. A NO2Cl g
  2. B NO2 g
  3. C Cl2 g
  4. D Cl g
Verified Solution

Answer & Solution

Correct Answer

(D) Cl g

Step-by-step Solution

Detailed explanation

\(NO _2 Cl \xrightarrow{K_1} \stackrel{\bullet}{ NO }_2(g)+\underset{\text { (free radical) }}{\stackrel{\bullet}{ Cl }(g)}\)
\(\stackrel{\bullet}{ NO }_2 Cl ( g )+\stackrel{\bullet}{ Cl }( g ) \xrightarrow{ K _2} NO _2(g)+ Cl _2(g)\)
The intermediate generated is \(\stackrel{\bullet}{Cl}\).