MHT CET · Chemistry · Solutions
According to Raoult's law mole fraction of solute in solution is given by formula
- A \(\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}\)
- B \(\frac{\mathrm{P}_1^0}{\mathrm{P}_1}\)
- C \(\frac{\mathrm{P}_1^0}{\Delta \mathrm{P}}\)
- D \(\frac{\mathrm{P}_1}{\mathrm{P}_1^0}\)
Answer & Solution
Correct Answer
(A) \(\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}\)
Step-by-step Solution
Detailed explanation
\(P_1=\) Vapour pressure of solution
\(\mathrm{P}_1^0=\) Vapour pressure of pure solvent
Mole fraction of solute \(=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0}=\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}\)
\(\mathrm{P}_1^0=\) Vapour pressure of pure solvent
Mole fraction of solute \(=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0}=\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}\)
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