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MHT CET · Chemistry · Chemical Equilibrium

A weak monobasic acid dissociates to \(0.001 \%\) in its \(0.01 \mathrm{M}\) solution. What is its dissociation constant?

  1. A \(1 \times 10^{-6}\)
  2. B \(1 \times 10^{-8}\)
  3. C \(1 \times 10^{-3}\)
  4. D \(1 \times 10^{-12}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1 \times 10^{-12}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{K}_{\mathrm{a}}=\propto^2 \mathrm{C} \\ & =\left(\frac{0.001}{100}\right)^2 \times 0.01 \\ & =1 \times 10^{-12}\end{aligned}\)