MHT CET · Chemistry · Chemical Equilibrium
A weak monobasic acid dissociates to \(0.001 \%\) in its \(0.01 \mathrm{M}\) solution. What is its dissociation constant?
- A \(1 \times 10^{-6}\)
- B \(1 \times 10^{-8}\)
- C \(1 \times 10^{-3}\)
- D \(1 \times 10^{-12}\)
Answer & Solution
Correct Answer
(D) \(1 \times 10^{-12}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{K}_{\mathrm{a}}=\propto^2 \mathrm{C} \\ & =\left(\frac{0.001}{100}\right)^2 \times 0.01 \\ & =1 \times 10^{-12}\end{aligned}\)
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