MHT CET · Chemistry · Thermodynamics (C)
A system given out \(\mathrm{x} \mathrm{J}\) of heat and does \(\mathrm{y} \mathrm{J}\) of work on it's surrounding. What is the internal energy change?
- A \(-x-y ~ J\)
- B \(y-x ~ J\)
- C \(x-y ~ J\)
- D \(x+y ~ J\)
Answer & Solution
Correct Answer
(A) \(-x-y ~ J\)
Step-by-step Solution
Detailed explanation
\(\mathrm{q}=-\mathrm{xJ}\) Heat released by system \((-)\) ve \(\mathrm{w}=-\mathrm{yJ}\) Work done by system \((-)\) ve From first law of thermodynamics.
\(
\begin{aligned}
& \Delta \mathrm{U}=\mathrm{q}+\mathrm{w} \\
& =-\mathrm{x}-\mathrm{y} \mathrm{J}
\end{aligned}
\)
\(
\begin{aligned}
& \Delta \mathrm{U}=\mathrm{q}+\mathrm{w} \\
& =-\mathrm{x}-\mathrm{y} \mathrm{J}
\end{aligned}
\)
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