MHT CET · Chemistry · Solutions
A solution of nonvolatile solute is obtained by dissolving \(3.5 \mathrm{~g}\) in \(100 \mathrm{~g}\) solvent has boiling point elevation \(0.35 \mathrm{~K}\). Calculate the molar mass of solute.
\(\left(\right.\) Molal elevation constant \(\left.=2.5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)\)
- A \(270 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(260 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(250 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(240 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(C) \(250 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{M}_2=\frac{\mathrm{K}_{\mathrm{b}} \times \mathrm{W}_2 \times 1000}{\Delta \mathrm{T}_{\mathrm{b}} \times \mathrm{W}_1}=\frac{2.5 \times 3.5 \times 1000}{0.35 \times 100}=250 \mathrm{~g} \mathrm{~mol}^{-1}\)
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